Question

i) As the electron revolves in the second Bohr orbit of the hydrogen atom, the corresponding current
is 1.3 * 104 A. If the area of the orbit is 1.4 x 10-19 m², what is the equivalent magnetic momentur
a) 1.82 x 10-23 Am2
b) 1.82 x 10-15 Am2
c) 2.82 x 10-23 Am²
d) 2.82 x 10-15 Am2​

Answer 1

Answer:

a) 1.82*10-23Am2?????????

Answer 2

The magnetic moment is (B) 1.82 × 10⁻¹⁵ Am².

Given:

Current $=1.3$ ×$10^{4}A$

Area of the orbit $=1.4$ × $10^{-19}m^{2}$

To find:

Magnetic moment

Solution:

The magnetic moment is the strength of the magnetic field or the energy of the magnet to produce a magnetic field.  

Mathematically, magnetic moment μ $=IA$

We have the value of current and area . Hence,

μ $=1.3$ × $10^{4}$ × $1.4$ × $10^{-19}$

μ $=1.82$ × $10^{-19+4}$

μ $=1.82$ × $10^{-15} Am^{2}$

Final answer:

Hence, the equivalent magnetic moment for the electron is (B) 1.82 × 10⁻¹⁵ Am².