Physics, asked by sujalpathak514, 9 months ago

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Answered by Anonymous
1

The number of significant figures in the given quantities . are given below.

(i) In 0.007, the number of significant figures is 1

because in a number less than 1, the zero’s on the right of the decimal point but to the let of the first non-zero digit are not significant.

(ii) In 2.64 X${{10}^{24}}$, the number of significant figures is 3. because all non-zero digits are significant, power of 10 are not taken in significant figure.

(iii) In 0.2370, the number of significant figures is 4, as all non-zero digits left to decimal and trailing zero are significant.

(iv) In 6.320, the number of significant figures is 4 (reason is same as in part ‘c ’)

(v) In 6.032, the number of significant figures is 4 (reason is same as in part c: ')

(vi) In 0.0006032, the number of significant figures is 4 (reason is same as in part ‘a’).

Answered by MysteriousAryan
0

Answer:

1)2 \\ 2)8 \\ 3)0.8

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