I borrowed ₹12,000 at 10% per annum simple interest for 2 years. Had I borrowed this sum at 10% per annum compound interest for 2 years, then the extra amount I have to pay will be ?
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Answer:
Step-by-step explanation:
principal(p)=12000, rate (r)=10%, time=2years(n=2)
simple interest=(principal*rate*time)/100
= (12000*10*2)/100
= 2400
compound interest= {p(1+r/100)^n}-p
={12000-(1+10/100)^2} - 12000
=14520-12000
= 2520
hence in compound interest is more than simple interest by 2520-2400
= 120 rupees extra.
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