Question

I bought a certain number of apples at four for 6 paise, and three-fifths
of that number at there for 6 paise; by selling them at sixteen for 30
paise I gained 24 paise; how many apples did I buy?​

Answer 1

Answer:

Let first bunch of apples bought be X. Then second bunch of apples bought is (3X/5). So, total selling apple is (X+3X/5)=8X/5.Cost price per apple of first bunch is (6/4) paise per apple that is 1.5 paise per apple.So in equation total cost price of first bunch of apples is 1.5X.Cost price per apple of second bunch is (6/3) paise per apple that is 2 paise per apple and in second bunch (3/5) th of first bunch is bought. So total cost price of second is (2*3x/5)=6x/5.

selling price per apple is (30/16) paise and total selling apple is 8x/5

the equation is total selling price-total cost price because there's total 24 paise gain in question.so

{(30/16)*(8x/5)} - {(1.5x+6x/5)}=24

so X=80 from solving that equation is first bunch of apples bought

and so 3x/5 = 3*80/5=48 that is second bunch of apples bought.

now total numbers of apples bought is 80+48=128 apples.

Step-by-step explanation: