Chemistry, asked by vhariharan04, 9 months ago

i) C20- + Cr, 0,2- → Cr3+ + CO, (in acid medium)

Answers

Answered by azaanmds98

1

Cr2O72- + H2C2O4 → Cr3+ + CO2. Step 2. Separate the redox reaction into ... 3*0 + 1*-2 + 8*1 = 6*0 + 2*3 + 7* 0.

Answered by prabhdayal

1

Answer:

Cr2O72- + 3H2C2O4 + 8H+ → 2Cr3+ + 6CO2 + 7H2O

Explanation:

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