Question

(i) Calculate the amount of each reactant required to produce 950 mL of carbon dioxide according to the following equation: [2] 2 CO + O2  2 CO2 (ii) Name the law associated in (i). [1] (iii) State the law named above.

Answer 1

Given:

The reaction:  2 CO + O2 → 2 CO2

The volume of CO2 = 950 ml = 0.95 L

To Find:

The amount of each reactant required to produce 950 mL of carbon dioxide.

Calculation:

No of moles of CO2 in 0.95 L = 0.95/22.4 = 0.04241 moles

- According to the following reaction:

- No of moles of O2 required to produce 2 moles of CO2 = 1

⇒ No of moles of O2 required to produce 0.04241 moles of CO2 = (1/2) × 0.04241

⇒ N(O2) = 0.0212

- No of moles of CO required to produce 2 moles of CO2 = 2

⇒ No of moles of CO required to produce 0.04241 moles of CO2 = (2/2) × 0.04241

⇒ N(CO) = 0.04241

- So, the required no of moles of CO and O2 are 0.04241 and 0.0212 respectively to produce 950 ml of CO2.