Question

(i) Calculate the area of quad. ABCD, given in Fig. (i).
(ii) Calculate the area of trap. PQRS, given in Fig. (ü).
R
S
8 cm
17 cm
C
17 cm
8 cm
9 cm
B
T
8 cm
8 cm
P
A
(ii)
(0)​

Answer 1

Answer:

(i) 

ar(quad. ABCD) = ar(∆ ABD) + ar(∆ BDC)

∆ABD and ∆BDC are right angle triangles.

So, BD = 

and AB = 

Now,  ar(∆ABD) = ⨯AD ⨯ AB 

=  ⨯9 ⨯ 12

= 54 cm2

Also, ar(∆BDC) = ⨯BD ⨯ BC 

=   ⨯15 ⨯ 8

= 60 cm2

Hence, area of quad. ABCD = 54 + 60 = 114 cm2

(ii) 

ar(quad. PQRS) = ar(rectangle PTRS) + ar(∆TRQ)

∆TRQ is a right angle triangle.

So, TR = 

Now, ar(rectangle PQRS) = length ⨯ height

= PT ⨯ TR 

= 8 ⨯ 15

= 120 cm2

Also, ar(∆ TRQ) =  ⨯ TQ ⨯ TR 

=  ⨯8 ⨯ 15

= 60 cm2

∴ ar(quad. PQRS) = 120 +60 = 180 

Answer 2

Answer:

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Step-by-step explanation:

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