Question

i) Calculate the empirical and molecular formula of a compound having
the following percentage composition
C = 26.59% H= 2.22% O= 71.19%
Vapour density is 45

ii) Calculate the percentage composition of
Potassium chlorate
k= 39, C1 = 35.5, O = 16

iii) Show the formation of ammonium ion

iv) Give any 2 conditions for the formation of a covalent bond​

Answer 1

Answer:

2) formula=KClO3

firt we calculate the molar mass of compound.

$39 + 35.5 \times 16(3) = 122.5$

then we calculate the percentage of each one.

$39 \div 122.5 \times 100 = 31.83\%$

$35.5 \div 122.5 \times 100 = 28.97\%$

$48 \ \div 122.5 \times 100 = 39.18\%$

K=31.83%, Cl=28.97%, O=39.18%

4) the covalent bonds formed between two non metals.

the atoms having no tendency to loose electrons.

3) Ammonium ion can be formed by transfer H+ ion to NH3 from HCl.