i) calculate the number of atoms present in 6 gram atom of calcium ii) calculate the number of gram atom present in 18.069 * 10^24 atom of mg
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HERE IS YOUR ANSWER :-
1) mass in gram / atomic mass in gram = No of atom/ 6.023 * 10^23
6/12 = no of atom / 6.023 * 10^23
1/2 = no of atom / 6.023 * 10^23
no of atom = 6.023 * 10^23 /2
no of atom = 3.01 * 10^23
ii) mass in gram / atomic mass in gram = no of atom / 6.023 * 10^23
mass in gram /24 = 18.069 * 10^24/ 6.023 * 10^23
mass in gram /24 = 3 * 10
mass in gram /24 = 30
mass in gram = 30 * 24
mass in gram = 720 g
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HERE IS YOUR ANSWER :-
1) mass in gram / atomic mass in gram = No of atom/ 6.023 * 10^23
6/12 = no of atom / 6.023 * 10^23
1/2 = no of atom / 6.023 * 10^23
no of atom = 6.023 * 10^23 /2
no of atom = 3.01 * 10^23
ii) mass in gram / atomic mass in gram = no of atom / 6.023 * 10^23
mass in gram /24 = 18.069 * 10^24/ 6.023 * 10^23
mass in gram /24 = 3 * 10
mass in gram /24 = 30
mass in gram = 30 * 24
mass in gram = 720 g
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I HOPE IT MAY HELPFUL FOR YOU ✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌
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