Question

I. Calculate the number of moles and
molecules of acetic acid present in 22 g
of it.
(Ans. : 0.3666 moles, 2.2076 x 1023
molecules )​

Answer 1

Explanation:

Acetic Acid=CH3COOH

{Molar Mass=12+3+12+16+16+1=60

Moles= Mass/Molar Mass

Moles= 22/60

Moles= 0.3666 moles

1 Mole= 6.022×10²³

So 0.3666 moles=0.3666 ×6.022×10²³= 2.2076×10²³