Question

(i) Calculate the potential at a point P due to a charge of 4×10-⁷c located 9 cm away (ii) Hence obtained the work done is bringing a charge of 2x 10-⁹ c from infinity to the point P. Does the answer depend on the path along which the charge is brought​?

Answer 1

Answer:

(a) Potential at point P✌☝️

(b) Work done in bringing charge

$\red{ \tt {\huge{ \bf2 × 10^{-9} C}}}$

from infinity to point P

$\purple{ \huge \sf{W = qVc}}$

$\huge \bf \color{cyan}= 2 \times 10^{-9 }C × 4 × 10^4$

${ \cal {\pink {\huge{ \fbox V = 8 × 10^5 J}}}}$

This work done does not depend on path follows.

Explanation:

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Answer 2

Answer:(a) Potential at point P

V=1/4 pie E0 * Q/r

=9*10^9Nm^2C^-2 * (4*10^-7/0.09)

=4*10^4V

(b) Work done in bringing charge 2 × 10-9 C from infinity to point

P W = qV = 2 10-9 C × 4 × 104 V = 8 × 105 J

This work done does not depend on path follows