(i) Calculate the time in which the electron would acquire a velocity double of its initial
velocity.
(ii) How much distance the electron would cover in this time
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V=u+at
10^4=5 × 10^4 +10^4t
T=6 sec
s=ut+1/2at^2
s=4.8 × 10^5 m
10^4=5 × 10^4 +10^4t
T=6 sec
s=ut+1/2at^2
s=4.8 × 10^5 m
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