Question

I can't find the answer of this questioning

Answer 1

HERE IS YOUR ANSWER..⬇⬇

$\underline{SOLUTION}$ ➡

$3(y - 5) {}^{2} + 5y = (2y - 3) {}^{2} - (y + 1) {}^{2} + 1 \\ \\ = > 3(y {}^{2} - 2 \times y \times 5 + 5 {}^{2} ) + 5y = [(2y) {}^{2} - 2 \times 2y \times 3 + 3 {}^{2} ] - (y {}^{2} + 2 \times y \times 1 + 1 {}^{2} ) + 1 \\ \\ = > 3(y {}^{2} - 10y + 25) + 5y = (4y {}^{2} - 12y + 9) - (y {}^{2} + 2y + 1) + 1 \\ \\ = > 3y {}^{2} - 30y + 75 + 5y = 4y {}^{2} - 12y + 9 - y {}^{2} - 2y - 1 + 1 \\ \\ = > 3y {}^{2} - 25y + 75 = 3y {}^{2} - 14y + 9 \\ \\ = > - 25y + 75 = - 14y + 9 \\ \\ = > - 25y + 14y = 9 - 75 \\ \\ = > - 11y = - 66 \\ \\ = > y = \frac{ - 66}{ - 11} \\ \\ = > y = 6$

$\underline{ANSWER}$ ➡ $y = 6$

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