i cant find the sum of two numbers that equal 22 and their difference is 6
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let the two numbers be x and y
given that
x + y = 22 -----(1)
x - y = 6 ------ (2)
adding (1) and (2)
2x = 28
x = 28/2
x = 14
substitute value of x in (1)
14 + y = 22
y = 22 - 14
y = 8
the numbers are 14 and 8
Answered by
1
Answer:
The required numbers are 14 and 8
Step-by-step explanation:
Let a number to be x and other number to be y where x>y
since , sum of both numbers is 22 and their difference is 6, now according to question ,
x + y = 22..............(1)
and
x-y = 6 ...................(2)
By adding equtions 1 and 2 , we get
(x + y ) + ( x - y) = 22 + 6
2x = 28
therefore , x = 14
now putting x= 14 in eqution ( 1) , we get
14 + y = 22
therefore , y = 22-14 = 8
thus , the number are x= 14 and y = 8
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