Question

i cant solve it....plz answer this question

Answer 1

The money invested by Sachin may be form a sequence that is

5000,7000,9000,............upto 12 month

Now here, the common difference is same at all i.e 2000

So,

a=5000

c.d=2000

n=12

total money invested by Sachin

$= > \frac{n}{2} (2a + (n - 1)d) \\ = > \frac{12}{2} (2 \times 5000 + (12 - 1)2000) \\ = > 6(10000 + 11 \times 2000) \\ = > 6(10000 + 22000) \\ = > 6 \times 32000 \\ = > 192000$

I hope this helps you...