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cow 200
horse 280......
let the cost of cow is x
2x + x +80 =680
3x +80 = 680
3x=600
x=200
the cost of cow will be 200 .
and of horse is 280.
horse 280......
let the cost of cow is x
2x + x +80 =680
3x +80 = 680
3x=600
x=200
the cost of cow will be 200 .
and of horse is 280.
Answered by
4
Let the cost of a horse be Rs.x.
Let the cost of two cows be Rs.2y
x + 27 = Rs.680.... (1)
x - y =Rs.80 ... (2)
.................................
3y = Rs. 600
So y = Rs.200
x - 200 = 80
x = 280
x : y = 280 : 200
= 7 : 5
Therefore two cows =2y that is 200+200=400 and one horse is x that is 280
Since 400+280=680
Let the cost of two cows be Rs.2y
x + 27 = Rs.680.... (1)
x - y =Rs.80 ... (2)
.................................
3y = Rs. 600
So y = Rs.200
x - 200 = 80
x = 280
x : y = 280 : 200
= 7 : 5
Therefore two cows =2y that is 200+200=400 and one horse is x that is 280
Since 400+280=680
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