I challenge You all to solve this question. What is the Ratio in above question? Whoever will solve this I will mark him Brainliest.
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HELLO FRIEND,
HERE IS YOUR SOLUTION,
DE || BC and AD : DB = 5 : 4
Now, ∠ADE = ∠ABC and ∠AED = ∠ACB [Corresponding angles]
In △ ADE and △ ABC, we have
∠ADE = ∠ABC,
∠AED = ∠ACB and
∠A = ∠A [Common]
So, △ ADE ~ △ ABC [By AAA similarity]
⇒AD/AB=DE/BC
Given,AD/BD=5/4
⇒BD/AD=4/5
Now, adding 1 on both sides,we get
BD/AD +1 = 4/5 +1
⇒AB/AD = 9/5 = DE/BC
Again, In △ DEF and △ BCF, we have
∠EDF = ∠BCF [Alternate interior angles]
∠DFE = ∠BFC [Vertically opposite angles]
and ∠DEF = ∠FBC [Alternate interior angles]
So, △ DEF ~ △ BCF [By AAA similarity]
⇒ar(tri. DEF)/ ar(tri. BCF) = (DE/BC)^(2)
⇒ = (5/9)^(2)
⇒ = 25/81
I HOPE IS WILL HELPFUL TO YOU
I M' SO SORRY MODERATOR, I DIDN'T SEE WHAT IS GIVEN BUT TO SOLVE THIS ALL THE PROCESS IS SAME AND SAME THING TO DO ANOTHER QUE. TOO WHICH IS LIKE THIS ......
HERE IS YOUR SOLUTION,
DE || BC and AD : DB = 5 : 4
Now, ∠ADE = ∠ABC and ∠AED = ∠ACB [Corresponding angles]
In △ ADE and △ ABC, we have
∠ADE = ∠ABC,
∠AED = ∠ACB and
∠A = ∠A [Common]
So, △ ADE ~ △ ABC [By AAA similarity]
⇒AD/AB=DE/BC
Given,AD/BD=5/4
⇒BD/AD=4/5
Now, adding 1 on both sides,we get
BD/AD +1 = 4/5 +1
⇒AB/AD = 9/5 = DE/BC
Again, In △ DEF and △ BCF, we have
∠EDF = ∠BCF [Alternate interior angles]
∠DFE = ∠BFC [Vertically opposite angles]
and ∠DEF = ∠FBC [Alternate interior angles]
So, △ DEF ~ △ BCF [By AAA similarity]
⇒ar(tri. DEF)/ ar(tri. BCF) = (DE/BC)^(2)
⇒ = (5/9)^(2)
⇒ = 25/81
I HOPE IS WILL HELPFUL TO YOU
I M' SO SORRY MODERATOR, I DIDN'T SEE WHAT IS GIVEN BUT TO SOLVE THIS ALL THE PROCESS IS SAME AND SAME THING TO DO ANOTHER QUE. TOO WHICH IS LIKE THIS ......
Kundank:
no prblm i will manage that
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