Question

I challenge you cannot answer it


Pramod borrowed rupees 60000 at 12% per annum compounded 50% of the borrowed at the end of first year and 50% of the remaining loan at the end of the second year, find the amount of loan outstanding at the beginning of the third year


Dont copy from web

Answer with step by step explanation

please answer it fast

Answer 1

Answer:

Step-by-step explanation:

60000+3600(12% of 30000) = 63600

63600+3816(12% of 31800)   = 67416 Ans

Answer 2

Answer:

Answer will be 18816

Step-by-step explanation:

At the end of 1st year the amout increses to=

60000(1+12/100)=60000×112/100=67200

then pramodh pays 50% of the loan at the end of 1st year.

then the amount becomes=67200×(100-50)/100=67200×50/100=33600

Then again, end of the 2nd year the amout increses to= 33600×(1+12/100)=33600×112/100

=37632

Then again pramodh pays 50% of his remaining loan.

Then tha amout becomes= 37632×50/100=18816

So the amout of loan outstanding at the beginning of the 3rd year is=

18816