I challenge you to answer this Question of logarithm
Attachments:
Answers
Answered by
1
firstly we write 9 = 3^2
and then we also write it as 1 /3^-2
let it be (1/3)^-2
now base are same and equate powers
we get ,x +2/2 -x > -2
x+2 > -4 +2x
6 > x
so value of x is less than 6
and then we also write it as 1 /3^-2
let it be (1/3)^-2
now base are same and equate powers
we get ,x +2/2 -x > -2
x+2 > -4 +2x
6 > x
so value of x is less than 6
forjee:
But answer is x € (2,6) ------ How?
Answered by
0
I accept the challenge dear.......!!!!!!
Similar questions