Question

I challenge you to solve this if you can.can you solve this.
​

Answer 1

hey mate!

here is your answer:

a)between M and N

3ohm and 3ohm are in series

so, effective resistance=3+3=6ohm

now, 6ohm is parallel to 6ohm

so, effective resistance =1/6+1/6=2/6=1/3=3ohm

now, 3ohm and 3 ohm are in series

so, effective resistance =3+3=6ohm

now, 6ohm is parallel to 6ohm

so, effective resistance =1/6+1/6=1/3=3ohm

thus , resistnace between M and N is 3ohm

b) between M and A

we have effective resistance between m and n as 3ohm

so, now 3ohm is in series with 3ohm resistance

so, effective resistance =3+3=6ohm

now, 6ohm is parralel to 6ohm

so,effective resistance=3ohm

now, 3 ohm is in series with 3ohm

so, effective resistance =6ohm

now, 6ohm is in parallel with 3ohm

so, effective resistance is 1/6+1/3=1+2/6=3/6=1/2=2ohm

thus effective resistance between M and A is 2ohm

hope it helped ^_^

Answer 2

Btw m and n it is 3ohm and between m and a it is 5 ohm

Is it correct?