Question

(i) Change in velocity during t = 6s to t = 8s
(ii) Average acceleration during t = 10s to
t = 12s.
(iii) in which time interval acceleration will
be zero.
(iv) Acceleration during t = 14 s to t = 16 s.​

Answer 1

Answer:

1) 30 m/s.

2) 0 m/ s².

3) 10 to 14 Dec.

4) -15 m /s²

Explanation:

1) change in velocity = final velocity -initial velocity

= 60-30

= 30 ans.

4) acceleration = change in velocity / time taken

= -30/2 m/s²

= -15 m/s²

Answer 2

(i)velocity in 6s=30 m/s

velocity in 8s=60 m/s

Between 6s and 8s change in velocity =60-30=30m/s

(ii)Velocity in 10s=30m/s

Velocity in 12s=30 m/s

Velocity change =30-30=0 m/s

Between these period velocity is constant so there is no change in velocity and acceleration is 0

(iii)Between 10s to 14s

Velocity is constant so acceleration is 0

(iv) a=v-u/t

Between 14s and 16s Velocity change =v-u

v=0 m/s

u=30 m/s

t=2s

a=0-30/2

a=-15 m/s^2

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