Math, asked by christinadcosta863, 3 months ago

(i) Complete the following activity.



Find my perimeter

and area

2y

2x + y +8

4x – y

I am a x + 4

Rectangle

Find the values

of x and y

In a rectangle, opposite sides are equal in length.

\ 2x + y + 8 = 4x – y

\ 2x – + y + = – 8

\ + 2y = – 8

\ 2( ) = – 8

\ =

–8

2 \ = – 4 ...(i)

Also, 2y = x + 4

\ – 4 = x –

i.e. x – 2y = – 4 ...(ii)

Adding (i) and (ii) we get,

– x + y = – 4

+ x – 2y = – 4

– y =

\ y =

Substituting y = in (i) we get,

– x + = – 4

\ – x = – 4 –

\ – x =

\ x =

\ The length of rectangle = 2x + y + 8

= 2( ) + + 8

= + 16

= 40 units
The breadth of rectangle = 2y

= 2 ×

= units

\ Perimeter of rectangle = 2 [length + breadth]

= 2 [ + ]

= 2 ×

\ Perimeter of rectangle = units

Area of rectangle = length × breadth

= ×

\ Area of rectangle = sq. units





pls help, it's urgent​

Answers

Answered by sashikaladash1983
0

Answer:

Area of rectangle = length × breadth

= ×

\ Area of rectangle = sq. units

pls help, it's urgent

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