Question

(i) Complete the following activity to find the length of diagonal of a rectangle whose length is 35 cm and breadth is 12 cm.​

Answer 1

Answer:

According to pythgoras theorem in tringle ABC

Step-by-step explanation:

ABsquare +BCsquare =ACsquare

Answer 2

$\frak{given} \begin{cases} \sf length \: of \: rectangle = \frak{35 \: cm} \\ \sf breadth \: of \: rectangle = \frak{12 \: cm} \end{cases}$

We are asked to find the Diagonal of this rectangle

⠀⠀⠀_____________________

So, here we are going to use Pythagoras theorem.

$\underline {\boxed {\pink{ {\frak{hypotenuse (h)^{2} = perpendicular(p) ^{2} + {base(b)}^{2} }}}}}$

we know that,

• perpendicular(DC) = 12 cm
• base(BC) = 35 cm
• Hypotenuse (BD) = ?

$\: \: \: \: \: \dag \: \underline \frak{substituting \: the \: values \: in \: formula}$

$: \implies \bf {BD}^{2} = {35}^{2} + {12}^{2}$

$: \implies \bf {BD}^{2} = 1225 + 144$

$: \implies \bf {BD}^{2} = 1369$

$: \implies \bf BD = \sqrt{1369}$

$: \implies \boxed {\pink{{ \frak{diagonal(BD) =37 cm }}}} \bigstar$

$\therefore \underline{ \sf our \: required \: answer \: is \: 37 \: cm}$

⠀⠀⠀⠀_____________________

I hope it's beneficial :D