Question

(i) Consider a conductor of resistance ‘R’, length ‘L’, thickness‘d’ and resistivity ‘ρ’.

Now this conductor is cut into four equal parts. What will be the new resistivity of

each of these parts? Why?

(ii) Find the resistance if all of these parts are connected in:

(a) Parallel

(b) Series

(iii) Out of the combinations of resistors mentioned above in the previous part, for a

given voltage which combination will consume more power and why?​

Answer 1

Answer:

a) the resistance will be 1/16 ohms

Explanation:

if the resistor is cut each part will be = 1/4 ohms

therefore

1/Req=1/1/4+1/1/4+1/1/4+1/1/4

1/Req=16ohms

Req=1/16ohms

b) the resistance will be 1ohm

Req= 1/4+1/4+1/4+1/4

=1ohm