Question

(i)Construct an angle 22½0
(ii) Construct a ABC whose perimeter 10cm, B = 30 and C = 600​

Answer 1

(i) Construct an angle 22½∘

Step 1: A ray from OB is drawn.

Step 2: Draw a perpendicular bisector to the line A′

B.Join AO and AB

Step 3: Draw a perpendicular bisector to the line AB then ∠BOD=45∘

∴∠BOD=45∘

Step 4: Draw a perpendicular bisector to the line BD  

∴∠BOC=22.5∘

Thus,∠BOC is the required angle making 22.5∘

(ii) Construct a ABC whose perimeter 10cm, B = 30∘  and C = 600∘

Draw a line segment, say XY equal to BC + CA + AB = 10 cm.

Make angle LXY equal to 60o and angle MYX equal to 45o.

Bisect  LXY and MYX. Let these bisectors intersect at point A.

Draw perpendicular bisector PQ of AX and RS of AY.

Let PQ intersect XY at B and RS intersect XY at C.

Join AB and AC.

ABC is the required triangle.

There are 2 images attached. The first image is for the first answer and the second image for the second answer.