Math, asked by gjgoutam12345, 10 months ago

i) cos 306° + cos 234° + cos 162° + cos 18° = 0​

Answers

Answered by umamaram1984
11

Answer:

0

Step-by-step explanation:

cos306°+cos234°+cos162°+cos18°

=cos(360°+54°)+cos(180°+54°)+cos(180°-18°)+cos18°

=cos54°-cos54°-cos18°+cos18°

=0

Answered by amansah624
0

Answer:

0

Step-by-step explanation:

cos 306°+ cos 234°+cos 162°+cos 18°

= cos(360-54)+cos(180+54)+cos(180-18)+cos 18

= cos 54 - cos 54 - cos 18 +cos 18

= 0

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