Question

(i)
cos (90° - A) sin (90° - A)
tan (90° - A)
= 1 – cos² A

Guys answer it fast!!!!!!!
Hurry up!!!! ​

Answer 1

LHS

cos(90°-A)=sinA

sin (90°-A)= cosA

tan(90°-A)= cotA

sinA*cosA*cotA

1*cosA/sinA

RHS

1-cos2A = sin2A