Math, asked by gyan214, 4 months ago

(i) cos'A-sin'A = cos 2A
(1-sin? 2A

Answers

Answered by shivali9

1

Step-by-step explanation:

1+sin2A−cos2A1+sin2A+cos2A

=sin2A+1−(1−2sin2A)sin2A+1+2cos2A−1

=2sinAcosA+2sin2A2sinAcosA+2cos2A

=2sinA(cosA+sinA)2cosA(sinA+cosA)

=sinAcosA=cotA.

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