(i) cos B
From the following figure, find the values of:
(ii)
tan c
iii) sin-B + cos²B
iv) sin B.cos C + cos B.sin C
А
8
B
с
17
Answers
Answered by
1
Step-by-step explanation:
In △ABC, AD⊥BC AB=13, BD=5, DC=16
Now, In △ABD,
AB
2
=AD
2
+BD
2
13
2
=AD
2
+5
2
AD
2
=144
AD=12
Now, in △ADC,
AC
2
=AD
2
+CD
2
AC
2
=12
2
+16
2
AC
2
=144+256
AC=20 cm
Now, sin
2
C+cos
2
C=(
H
P
)
2
+(
H
B
)
2
=(
AC
AD
)
2
+(
AC
BD
)
2
= (
20
12
)
2
+(
20
16
)
2
=
400
144
+
25
256
=
400
400
= 1
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