(i) (cos0° + sin 45° + sin 30°)(sin 90º – cos 45º + cos 60°)
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Answered by
1
Answer:
may be my answer helps you
Step-by-step explanation:
(cos0
o
+sin45
o
+sin30
o
)(sin90
o
−cos45
o
+cos60
o
)
=(1+
2
1
+
2
1
)(1−
2
1
+
2
1
)
=(1+
2
1
+
2
1
)(1+
2
1
−
2
1
)
=(
2
3
+
2
1
)(
2
3
−
2
1
)
=(
2
3
)
2
−(
2
1
)
2
=
4
9
−
2
1
=
4
7
Answered by
1
Step-by-step explanation:
cos 0 = 1
sin 45 = 1/√2
sin 30 = 1/2
sin 90 = 1
cos 45 = 1/√2
cos 60 = 1/2
tq
i hope it help uu
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