Question

I couldn't solve this. Can anyone help? I need it to help a friend please.

Step by step explanation required!

Thanks in Advance.

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Answer 1

$\huge\mathfrak{\blue{\underline{\underline{Answer}}}}$

unnie I got answer.....

Its here.....↓↓↓↓

=>6abc+_____+2b²C+8abc-14b³a=15b²c+_____20abc-12abc

=>-8abc+_____+2b²c+8abc

=15abc_______+8abc.

in above step +8abc & + 8abc will cut out as the are in same veriables and constants.

=>-8abc+______+2b²c=15b²c_____

=>Adding (-8abc) in left side and subtracting -13b²c in the right side so that all the digits are cancle out.

=>-8ab³+8ab³+2b²c=15b²c+(-13b²c)

=>2b²c=15b²c-13b²c

=>2b²c=2b²c

=>0=0

L.H.S=R.H.S

:.guven statement is true now.

please check it is correct or not...

Answer 2

$\huge\underline\mathfrak{\pink{A}\blue{N}\purple{S}\orange{W}\red{E}\green{R}}$

Your Question -

• 6ab³+____+2b²c+8abc-14b³c = 15b²c+____+20abc-12abc

• 6ab³+____+2b²c+8abc-14b³a = 15b²c+____+20abc-12abc

• =>6ab³+____+2b²c+8abc-14a×b³=15b²c+____+20abc-12abc

• =>6ab³+____+2b²c+8abc-14ab³ = 15b²c+____+20abc-12abc

• =>-8ab³+____+2b²c+8abc=15b²c+____+8abc

• =>-8ab³+____+2b²c=15b²c+____+8abc-8abc

• => -8ab³+____+2b²c=15b²c+____

• => -8ab³+____=15b²c+(-2b²c)____

• => -8ab³+____=13b²c+____

${\green{\bold{\underline{to \: balance \: this \: equation, \:we'll \: add}}}}$

${\green{\bold{\underline{13b²c \: in \: LHS \: and \: -8ab²\: in \: RHS}}}}$

-8ab³+(13b²c)=13b²c+(-8ab³)

=> 0=0

=> LHS=RHS

$\red{ hence \: the \: equation \: is \: balanced \: now.}$

$\orange{ hope \: it \: helps}$

${\underline{\mathcal {\purple{purple \: you...}}}}$

$\orange{ slide \: left \: to \: right}$