Question

I'd 4 tan A = 3then coscA +sine open cos A- sin A is equal to​

Answer 1

If 4TanA = 3

⇒ Tan A = ¾ = perpendicular/base

then, by Pythagoras Theorem

⇒ (3)² + (4)² = (hypotenuse)²

⇒ hypotenuse = 5 units

then,

sin A = p/h = 4/5

cos A = b/h = 3/5

cosec A = h/b = 5/4

sec A = h/p = 5/3

cot A = b/p = 4/3

Answer 2

Answer:

Given 4Tanθ=3⇒Tanθ= 43

sinθ=53cosθ= 54

4sinθ+cosθ

4sinθ−cosθ = 4( 53 )+ 544( 53)− 54= 5

1658 = 21

Step-by-step explanation:

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