Math, asked by lalhriatzualifanai2, 4 hours ago

I'd be grateful if you help me. ​

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Answered by SaptakGhosh
2

Answer:

(a) \: x {}^{2}  - 7x + 12

 =  {x}^{2}  - 3x - 4x  + 12

 = x(x - 3) - 4(x - 3)

 = (x - 3)(x - 4)

(b) \: 4 {x}^{2}  - 4x + 1

 = 4 {x}^{2}  - 2x - 2x + 1

 = 2x(2x - 1) - 1(2x - 1)

 = (2x - 1)(2x - 1)

(c) \: 2 {n}^{2}  + 9n + 9

 = 2 {n}^{2}  + 6n + 3n + 9

 = 2n(n  + 3) + 3(n + 3)

 = (n + 3)(2n + 3)

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Answered by prabirkumarmondal2
0

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