Question

I dare you to answer this
4x^2-2(k+1)x+(k+1)=0

Answer 1

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Comparing the given equation with the general quadratic equation ax2 + bx + c = 0, we get,

a = 4, b = -2 (k + 1), c = k + 1

bhaiD = 0, for real and equal roots

4 (k + 1)2 - 16 (k + 1) = 0

4 (k + 1) (k + 1 - 4) = 0

(k + 1)(k - 3) = 0

k = -1, 3

Answer 2

Answer:

4x²-2(k+1) x+(k+1)

(2x) ²-(k+1) ²(x-2)

Step-by-step explanation:

k=-1,3