Question

(i) Define least count

(ii) The external and internal diameter of a hollow cylinder are determined with a vernier callipers . the result are recorded as 4.23 ± 0.01 cm and 3.89 ± 0.01 cm determine the thickness of the cylinder wall with limits of error .​

Answer 1

Explanation:

Least count is the smallest measurement that can be taken by a measuring instrument. ... The least count is related to the precision of an instrument; an instrument that can measure smaller changes in a value relative to another instrument, has a smaller "least count" value and so is more precise.

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Answer 2

Explanation:

(i) Least count is the smallest measurement that can be taken by a measuring instrument. ... The least count is related to the precision of an instrument; an instrument that can measure smaller changes in a value relative to another instrument, has a smaller "least count" value and so is more precise.

(ii) The thickness of cylinder wall with the error limits is equal to 0.34 +- 0.02.

The solution is as follow:

Internal diameter= 3.89+0.01 cm

External diameter=4.23+0.01 cm

 Thickness (t) = External- Internal

Therefore, t= 4.23-3.89= 0.34

Hence, thickness of cylinder wall with the error limits is equal to 0.34 plus minus 0.02 (0.01+0.01)