(i) Derive an expression for drift velocity of electrons in a conductor. Hence deduce Ohm’s law.
(ii) A wire whose cross-sectional area is increasing linearly from its one end to the other, is connected across a battery of V volts. Which of the following quantities remain constant in the wire?
A. drift speed
B. current density
C. electric current
D. electric field
Justify your answer.
Answers
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Given:
The drift velocity of electrons in a conductor.
To find:
(i) Derive an expression for drift velocity of electrons in a conductor. Hence deduce Ohm’s law.
(ii) A wire whose cross-sectional area is increasing linearly from its one end to the other is connected across a battery of V volts. Which of the following quantities remain constant in the wire?
A. drift speed B. current density C. electric current D. electric field
Solution:
(i)
Consider an electron of mass m and charge e moving inside a conductor with a drift velocity Vd when an electric field E is applied. (E = V/l)
Force on electron = -Ee
Acceleration of each electron = − Ee/m
Mechanical force on electron = ma
Velocity created due to this acceleration = [Ee/m] (τ)
where τ is the time span between two consecutive collisions.
This ultimately becomes the drift velocity in steady-state.
vd = [Ee/m] (τ) = (e/m)τ(V/l)
∴ vd = (e/m)τ(V/l)
We know that current in the conductor i = neA Vd
i = neA × e/m τ V/l
∴ i = ne²Aτ V/ml
⇒ i = V/R
where, R = ne²Aτ /ml
∴ i ∝ V
This is as per Ohm's Law.
(ii)
A wire whose cross-sectional area is increasing linearly from its one end to the other is connected across a battery of V volts.
As the current does not depend on the area of cross-sections of the wire,
We know, I = dq/dt, the rate of flow of charge, where as the drift speed, current density and electric field depends on the increasing area of cross-section with the following formula:
Drift speed = vd = I/Ane
Current density = I/A
Electric field - J/σ
The following quantities remain constant in the wire: drift speed, current density and electric field.