Question

(i) Derive error in division.

(ii) In an observation a percentage error in measurement of mass is 5% and in velocity is 2%. Find the
percentage error in kinetic energy.​

Answer 1

Explanation:

For small changes if Kinetic Energy =

2

1

mv

2

Then, Percentage error in Kinetic Energy = Percentage error in m+2×(Percentage error in V)

Now Percentage error in m=

50

0.5

×100=1%

Percentage error in V=

10

0.1

×100=1%

∴ Percentage error in Kinetic Energy =1%+2%=3%