Question

(i) Determine the nature of the roots for the quadratic equation
√3x² + √2x-2√3=0​

Answer 1

Answer:

Step-by-step explanation:

√3x² + √2x -2√3 = 0

a= √3

b= √2

c= -2√3

DISCRIMINANT = b²-4ac

= (√2)²-4(√3)(-2√3)

= 2+24

= 26

SINCE,

b²-4ac > 0

26 > 0

HENCE,

The quadratic equation has two distinct roots

HOPE THIS WILL HELP YOU☺️☺️