(i) Determine the nature of the roots for the quadratic equation
√3x² + √x – 2√3=0.
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kshitija5866
19.05.2019
Math
Secondary School
√3x^2 +√2x-2√3=0 determine the nature of roots for each of the quadratic equation
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smrutisubudhicreatea
smrutisubudhicreatea
Hope it helps u out.. Plsz inform if u don't understand I will be glad to clear it..
preeti99699
this is not an imaginary root it is a real and distinct root
erinna
The given quadratic equation have two distinct real root.
Step-by-step explanation:
The given quadratic equation is
\sqrt{3}x^2+\sqrt{2}x-2\sqrt{3}=0
A quadratic equation is ax^2+bx+c=0.
If b^2-4ac, then the equation have two complex roots.
If b^2-4ac=0, then the equation have equal real roots.
If b^2-4ac>0, then the equation have two distinct real roots.
In the given equation,
a=\sqrt{3},b=\sqrt{2},c=-2\sqrt{3}
b^2-4ac=(\sqrt{2})^2-4(\sqrt{3})(-2\sqrt{3})=2+24=26
Since b^2-4ac>0, therefore, the given quadratic equation have two distinct real root.