Chemistry, asked by dhanbad235, 1 month ago

I Determine the
strength of the given potassium permanganate (KNnO4) in g/ litre with the help of M/50 oxealic acid solutions

Answers

Answered by afzalasghardae
0

Explanation:

Indicator

KMnO4 is a self-indicator.

End Point

Colourless to permanent pink colour (KMnO4 in burette).

Procedure

  1. Weigh 1.260 g of oxalic acid crystals and dissove them in water to prepare 500 ml of M/50 oxalic acid solution using a 500 ml measuring flask. Rinse the pipette with the M/50 oxalic acid solution and pipette out 20 ml of it in a washed titration flask.
  2. Rinse and fill the burette with M/100 KMnO4 solution.
  3. Add one test-tube (~ 20 ml) full of dilute sulphuric acid (~ 2 M) to the solution in titration flask.
  4. Note the initial reading of the burette.
  5. Now add KMnO4 solution from the burette till a permanent light pink colour is imparted to the solution in the titration flask on addition of last single drop of KMnO4 solution.
  6. Note the final reading of the burette.
  7. Repeat the above steps 4-5 times to get a set of three concordan

Calculations

(a) Molarity of the KMnO4 solution

From the overall balanced chemical equation it is clear that 2 moles of KMnO4 react with 5 moles of oxalic acid.

Next calculations in second image

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