Question

I DI BUL) of the following questions:
1. In a AABC, if 3angleA = 4angleB = 6angleC then A:B:C = ?
(a) 3:4:6 (b) 4:3:2
(c) 2:3:4
(d) 6:4:3​

Answer 1

Answer:

Given parameters

In ΔABC,

3∠A = 4∠B= 6∠C

Let us consider x = 3∠A = 4∠B = 6∠C

x = 3∠A

∠A = x/3………………….(1)

x = 4∠B

∠B = x/4…………………..(2)

x = 6∠C

∠C = x/6…………………….(3)

By using angle sum property

∠A + ∠B + ∠C = 1800

Put the values of ∠A, ∠B, ∠C

x/3 + x/4 + x/6 = 1800

Let us find the L.C.M of 3,4,6 i.e 12

(4x + 3x + 2x)/12 = 1800

9x = 2160

x = 2400

Substitute the value of x in eqaution (1), (2) and (3)

∠A= x/3

∠A= 240/3 = 80°

∠B= x/4

∠B= 240/4= 60°

∠C= x/6

∠C= 240/6 = 40°