Question

i) Diagonals of a rhombus are 20 cm and 21 cm respectively, then find
the side of rhombus.​

Answer 1

Answer:

14.5 cm

Step-by-step explanation:

as diagonals bisects each other at 90 degree

hence by pythagoras theorem

10^2 + 10.5^2 = x^2

100 + 110.25=x^2

210.25=x^2

x=14.5 cm

Answer 2

$\bold{\bigstar{\fbox{\color{cyan}{answer}}}}$

→ As diagonals of rhombus

are perpendicular bisector of

each other

⇒ AO=10,OB=21/2

From pythagoras theorm

in △AOB

$\\ {ab}^{2} = {10}^{2} + \frac{ {21}^{2} }{4} = 100 + \frac{441}{4}$

${ab}^{2} = \frac{841}{4} \\ {ab}^{2} = \frac{29}{2}$

perimeter = 4×29/2=58

one side = 58 cm