Question

I didint understand this question
sum of the digits of a two digit number is 9.when we interchange thes digits,it is found that the resulting new number is greater than the original number by 27.what is the two digit number?

Answer 1

Answer:

x=3;y=6.

Step-by-step explanation:

let , the number be xy

then x+y=9-----eq(1)

the digit is 10x+y,interchange the digits then the number would be 10y+x.

by the problem,10y+x=10x+y+27

=>10y-y=10x-x+27

=>9y=9x+27

=>9y-9x=27

=>9(y-x)=27

=>y-x=27/9

=> y-x=3--------eq(2).

eq(1)-eq(2)

=>x+y-(y-x)=9-3

=>x+y-y+x=6

=>2x=6

=>x=6/2

=>x=3

put x in eq(2),

y-x=3

y-3=3

y=3+3

y=6.

therefore,x=3;y=6.

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