(i) Divide 12 into two parts such that their product is 32.
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Let x and 12-x be the required numbers such that x(12-x) = 32
We have 12x -x^2 = 32
Or x^2 - 12 x +32 = 0
Solving by splitting the middle term we get x = 8 or 4
Required numbers are 8 and 4
ᑭᒪᔕ ᗰᗩᖇK ᗰE ᗷᖇᗩIᑎᒪIEᔕT
We have 12x -x^2 = 32
Or x^2 - 12 x +32 = 0
Solving by splitting the middle term we get x = 8 or 4
Required numbers are 8 and 4
ᑭᒪᔕ ᗰᗩᖇK ᗰE ᗷᖇᗩIᑎᒪIEᔕT
Answered by
1
Step-by-step explanation:
let one number be x. Then the other number will be 12 - x. so the numbers are 4 and 8.
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