I do not get this at all please help me!
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in ∆ANM and ∆BPM ,
MA =MB (given)
angle NAM =angle MBP =90°(MA perpendicular to CN)
NM=MP (M is the mid point of NP)
. '. ∆ANM =~∆BPM (RHS congruency rule)
. '. angle ANM=angle BPM (C.P.C.T.)
that is , angle CNP =angle CPN
. '. CP=CN (side opposite to equal angles are equal)
in ∆if one side of opposite sides are equal then the the triangle is isosceles
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so.hence,proved
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this
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this is the answer give this the brillanist answer
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