Math, asked by Abhinav300, 1 year ago

I do not understand this question

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Answered by Anonymous
1
let sides of trapezium be a,b
area of trapezium
=[ (a+b)h]/2
=[(10+16)8]/2
=208/2
=104cm^2

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Anonymous: tq for marking brainliest
Answered by Anonymous
2
Heyyy!!!


Here is your answer

As mentioned above the image of the trapezium is in the attachment.


Solution for the above problem is below⤵⤵

Area of a trapezium =
 \frac{1}{2}  \times altitude(sum \: of \: the \: two \: parallel \: sides) \\  \\ altitude(distance \: between \: parallel \: sides) = 8c m\\  \\ side1 = 10 cm\\  \\ side2 = 16cm \\  \\ area =  \frac{1}{2}  \times 8(10 + 16) \\  \\  =  \frac{1}{2}  \times 8(26) \\  \\   = \frac{1}{2}  \times 208 \\  \\  = 104 {cm}^{2}
Hence area is 104 cm^2


Hope it helps you ✌✌


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