I don't know how to do it plzz tell me
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Step-by-step explanation:
since l is perpendicular bisector and p lies on it so
∠AOP =∠BOP
IN triangles AOP & BOP
AO=BO(l is perpendicular)
∠AOP=∠BOP
OP=OP(common)
therefore triangles AOP & BOP are congruent
AP=BP(C.P.C.T)(congruent parts of congruent triangles)
H/P
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