Question

I don’t know how to solve this problem

Answer 1

Answer:

Oooo thx you told......

What can we do in that......

Answer 2

Answer:

hey mate your answer is.....

Explanation:

$t = \frac{mv {}^{2} }{r} + mg \cos(theta) \\ let \: speed \: at \: the \: lowest \: point \: be \: v1 \\ v1 {}^{2} = v {}^{2} + 2gr(1 - \cos(theta) \\ = (v1)min \sqrt{5gr} \\ not \: complete \: its \: vertical \: circular \: path. \\ \\ hope \: it \: helps \: for \: understanding..........$