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Solution
Given :-
- Angle of triangle are, (3x - 2), 2(x +1), 10(x + 12)
Find, :-
- Value of x
- Every angle of given triangle.
- Show, that , given triangle is isosceles triangle.
Explanation
We Know,
Sun of all angle of any triangle always be 180° .
Let,
Angle of given triangle , is <A ,< B , <C.
Then,
==> A + B + C = 180° .
Where,
- A = (3x - 2) ,
- B = 2(x + 1)
- C = 10(x + 12)
Keep all above Values,
==> (3x - 2) + 2(x + 1) + 10(x + 12) = 180°
==> 3x - 2 + 2x + 2 + 10x + 120 = 180°
==> 15x + 120 = 180°
==> 15x = 180 - 120
==> 15x = 60
==> x = 60/15
==> x = 4 .
Since,
- Value of x be = 4 .
Now, Calculate avery angle.
For <A.
- <A = 3x - 2
keep value of x
==> <A = 3×4 - 2
==> <A = 12 - 2
==> <A = 10 °
For, <B
- <B = 2(x + 1)
keep value of x
==> <B = 2(4 + 1)
==> <B = 2 × 5
==> <B = 10 °
For, <C
- <C = 10(x + 12)
keep value of x
==> <C = 10(4+12)
==> <C = 10×16
==> <C = 160°
we know,
The angle opposite side to equal side are equal , then we can say that is isosceles triangle.
Hence
- These triangle be isosceles triangle.
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