Question

I don't want long explanation .....give me the ans shortly....

Answer 1

Here There is ∆ACE,∆FBD
GIVEN HERE IS ∆ACE + ∆FBD =360°
||PROOF||
WE KNOW THAT SUM OF ALL ANGLES OF TRIANGLE IS 180°
HERE GIVEN IS TWO TRIANGLES ∆ACE AND ∆FBD .
TWO TRIANGLES ANGLE =180°+180° =360°

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Answer 2

In ∆ACE (A+C+E)=180°  ...(1)    (Angle Sum Property)In ∆BFD (B+F+D)=180°  ...(2)    (Angle Sum Property)On Adding (1) and (2) , we get(A+B+C+D+E+F)=180°+180°(A+B+C+D+E+F)=360
Hence Proved
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